1.

calculate thenumberof moleculespresentin the 36 gwater .

Answer»

Solution :The moleculesweightof `H_(2) O=18`
Thus,18Gramsof ` H_(2)O`= 1moleof `H_(2)O`
`36"gramsof"H_(2) O = 1 " 2moleof " H_(2)O`
1moleof `H_(2) O`
`=6.023 xx 10^(23) ` MOLECULESOF `H_2O`.
`=1.204xx 10 ^(24)`moleculesof ` H_2 O`.


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