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Calculate wavelength for `2^(nd)` line of Balmer series of `He^(+)` ion |
Answer» `1/lambda=R(2)^(2)[1/n_(1)^(2)-1/n_(2)^(2)]` `n_(1)=2 n_(2)=4` `1/lambda=R(2^(2))[1/2^(2)-1/4^(2)]` `1/lambda=(3R)/(4) " " lambda=(4)/(3R)` Ans. |
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