1.

Calculate wavelength for `2^(nd)` line of Balmer series of `He^(+)` ion

Answer» `1/lambda=R(2)^(2)[1/n_(1)^(2)-1/n_(2)^(2)]`
`n_(1)=2 n_(2)=4`
`1/lambda=R(2^(2))[1/2^(2)-1/4^(2)]`
`1/lambda=(3R)/(4) " " lambda=(4)/(3R)` Ans.


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