1.

Calculatethe pHof 1.0 xx10 ^(-4) molar Solution ofHNO_(3).

Answer»

Solution :`[H^+]= 1.0xx10^(-4)`
`pH =- LOG _(10) [H^+]`
`=- log _(10) [1xx10^(-4)]`
`pH =-(log _(10)1-4log _(10)log _(10)^(10))`
`=0 +4xx log _(10)^(10)`
`=0+4xx1=4`
`pH = 4 `


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