Calculte the number of molecules of molecules of oxalic acid in 100 mL of 0.02 N oxalic acid soliution.

Calculte the number of molecules of molecules of oxalic acid in 100 mL

1.	Calculte the number of molecules of molecules of oxalic acid in 100 mL of 0.02 N oxalic acid soliution.
Answer» Correct Answer - `6.022xx10^(20)` Step I. Calculation of no. of moles of oxalic acid per litre of the solution. `"Molarity"=("No. of moles of oxalic acid")/("Volume of solution in litre")` `(0.01" mol L"^(-1))=("No. of moles of oxalic acid")/(1L)` No. of moles = 0.01 mol. Step II. Calculation of no. of molecules of oxalic acid per 100 mL of solution. 1000 mL of oxalic acid solution contains moles = 0.01 `"100 mL of oxalic acid solution contains moles"=(0.01)/(1000)xx100=0.001 mol` `therefore "Molecules of oxalic acid"=0.001xxN_(0)=10^(-3)xx6.022xx10^(23)=6.022xx10^(20)" molecules".`

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Calculte the number of molecules of molecules of oxalic acid in 100 mL of 0.02 N oxalic acid soliution.

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