1.

Certain force acting on a 20 kg mass changes its velocity from 5m/s to 2m/s calculate the work done by the force.

Answer»

SOLUTION :Given mass of the object (m) 20 kg
Initial velocity of the object (u) = 5 m/s
FINAL velocity of the object (v) = 2 m/s
According to work energy theorem, W = `1/2 mv^(2) - 1/2 mu^(2)`
Therefore = `1/2 xx 20g xx (2^(2) - 5^(2)) = 10 xx (4 - 25) = (10 xx -21)` W = -210 J


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