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Certain force acting on a 20 kg mass changes its velocity from 5ms^(-1) "to" 2ms^(1) Calculate the work done by the force. |
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Answer» Solution :Kinetic energy is given by the expression `(Ek)_(r) = 1/2 mv^(2)` (i) Kinetic energy when the object MOVING with a velocity `5 MS^(-1) (Ek)_(v) = 1/2 xx 20 xx (5)^(2) = 250 J` Kinetic energy when the object was moving with a velocity `2 ms^(-1)` `(Ek)_(2) = 1/2 xx 20 xx (2)^(2) = 40 J` |
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