1.

Compare the power used in the 2Omega resistor in each of the following circuits: a 6 V battery in series with 1 Omega and 2 Omegaresistors

Answer»

SOLUTION :As `1Omega` resistor and `2Omega`resistor are connected in series, the eqUivalent resistance `R_s = 1 + 2 = 3 Omega `
Now, the VOLTAGE of the battery V = 6 V So, the current FLOWING through the circuit,
`I_s = V/R_s= 6/3 =2 A`
In a series combination the same current 2 A flows through each resistor. Hence the current flowing through `2Omega` resistor is also 2 A.
`:.`Power used in `2 Omega` resistor,
`P_1 = I_s^2 R`
`=(2)^2 xx2 =8 W`


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