1.

Compare the power used in the 2Omega resistors in each of th following circuits : (i) a 6V battery in series with 1Omega and 2Omega resistor, and (ii) a 4 V battery in parallel with 12Omega and 2Omega resistors.

Answer»

Solution :Case [i]
Current in the circuit,
`I=V/(R_(1)+R_(2))=6/3=2A`
POWER used = `I^(2)R=(2)^(2)xx2=2xx2xx2=8W`
`R=1+2=3Omega`
`I=V/R=6/3=2A`
Therefore VOLTAGE across `2OMEGA` resistor = `1xx2=2xx2=4V`
`PI=VI=4xx2=8W`
Case [ii] `I_(2)=V/R_(2)=4/2=2A`
`P_(2)` across `2Omega` resistor = `4xx2=8W`
Therefore RATIO, `P_(1):P_(2)=8:8=1`


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