InterviewSolution
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InterviewSolution
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Complete the following `:` i.` ._(7)N^(14)+._(2)He^(4)rarr ._(8)O^(17)+……….` `ii. ` `._(92)U^(235)+._(0)n^(1) rarr ._(55)A^(142)+._(37)B^(92)+……….` `iii.` `._(29)Cu^(53)rarr ._(28)Ni^(53)+………………` `iv.` `2 ._(1)H^(3)rarr._(2)He^(4)+.....` `v.` `._(96)Cm^(246)+._(6)C^(12)rarr ._(102)No^(254)+...........` `vi.` `._(94)Pu^(239)+.......rarr._(96)Cm^(242)+._(0)n^(1)` `vii. ` `._(34)Se^(82)rarr ............ +2 ._(-1)e^(0)` |
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Answer» `i.` `._(7)N^(14)+._(2)He^(4)rarr ._(8)O^(17)`+........ or `._(7)N^(14)+._(2)He^(4)rarr._(8)O^(17)+._(Z)X^(m)` Equating mass number on both sides `14+4=17+mimpliesm=-1` Equating atomic number on both sides, `7+2=8+ZimpliesZ=-1` `:. X` is `._(1)X^(1) ,i.e., ._(1)H^(1)` . or `._(7)N^(14)+._(2)He^(4) rarr ._(8)O^(17)+._(1)H^(1)` `ii.` `._(92)U^(235)+._(0)n^(1) rarr._(55)A^(142)+._(37)B^(92)+.....` Equation is `._(92)U^(235)+._(0)n^(1)rarr``_(55)Cs^(142)+._(37)Rb_(92)+2._(0)n^(1)` `iii.` `._(29)Cu^(53) rarr`._(28)Ni^(53)+._(Z)X^(m)` Equating atomic number on both sides and mass number on both sides `Z=0 ` `m=0` `:. ` `._(29)Cu^(53) rarr ._(28)Ni^(53)+._(Z)X^(m)` Equating atomic number on both sides and mass number on bot sides `:. 2 ` `._(1)H^(3) rarr._(2)He^(4)+2 ._(0)n^(1)` `v.` Equating atomic number and mass number on both sides `._(96)Cm^(246)=._(6)C^(12)rarr ._(102)No^(254)+4._(0)n^(1)` `vi.` Equating atomic number and mass number on both sides `._(94)Pu^(239)+._(2)He^(4) rarr ._(96)Cm^(242)+._(0)n^(1)` `vii.` Equating atomic number and mass number on both sides. `._(34)Se^(82) rarr ._(36)Kr^(82)+2._(-1)n^(0)` |
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