Comprehension # 1 Read the following rules and answer the questions at the end of it. Electrons in various suborbits of an filled in increasing order to their energies. Pairing of electrons in various orbitals of a suborbit takes places only after each orbital is half-filled. No two electrons in an atom can have the same set of quantum number. The sub-shell that arises after f sub-shell is called g sub-shell.A. it contains 18 electrons and 9 orbitalsB. it corresponds to `l=4` and first occurs in `5th` energy levelC. a g-orbital can have maximum of two electronsD. all the above statements are true.

Comprehension # 1 Read the following rules and answer the questions at

1.	Comprehension # 1 Read the following rules and answer the questions at the end of it. Electrons in various suborbits of an filled in increasing order to their energies. Pairing of electrons in various orbitals of a suborbit takes places only after each orbital is half-filled. No two electrons in an atom can have the same set of quantum number. The sub-shell that arises after f sub-shell is called g sub-shell.A. it contains 18 electrons and 9 orbitalsB. it corresponds to `l=4` and first occurs in `5th` energy levelC. a g-orbital can have maximum of two electronsD. all the above statements are true.
Answer» Correct Answer - D for g - sub-shell `n=5` `l = 0, 1,2,3,4` `l=4` (g-subshell) number of electron `=2(2l+1) = 2xx9implies 18` number of orbital `=(2l +1) implies 9` any orbital can have more two electron.

Discussion

No Comment Found

Related InterviewSolutions

The ratio between the neutrons present in nitrogen atom and silicon atoms with number 14 and 28 is :A. `7:3`B. `3:7`C. `1:2`D. `2:1`
Which one of the following sets of ions represents the collection of isoelectronic species?A. `Na^(+),Mg^(2+),Al^(3+),Cl^(-)`B. `Na^(+),Ca^(2+),Sc^(3+),F^(-)`C. `K^(+),Cl^(-),Mg^(2+),Sc^(3+)`D. `K^(+),Ca^(2+),Sc^(3+),Cl^(-)`
If `I_(0)` is the threshold wavelength for photoelectric emission, 1 the wavelength of light falling on the surface of a metal and m is the mass of the electron, then the velocity of ejected electron is given byA. `[(2h)/(m)(lambda - lambda)]^(1//2)`B. `[(2hc)/(m)(lambda_(0)-lambda)]^(1//2)`C. `[(2hc)/(m){(lambda_(0)-lambda)/(lambda lambda_(0))}]^(1//2)`D. `[(2hc)/(m){(1)(lambda_(0))-(1)/(lambda)}]^(1//2)`
If the threshold wavelength `(lambda_(0))` for spection of electron from metal is `350nm `then work function for the photoelectric emission isA. `1.2 xx 10^(-18) J`B. `1.2 xx 10^(-20) J`C. `6 xx 10^(-29) J`D. `6 xx 10^(-12) J`
Which one of the following sets of ions represents a colloection of isoelectronic species ?A. ` K^+ , Cl^- , Ca^(2+) , Sc^(3+)`B. ` K^+ , Cl^- , Ca^(2+) , Sc^(2+), Sc^(3+)`C. `N^(3-), O^(2-) F^- , S^(2-)`D. `Li^+ , Na^+ , Mg^(2+) , ca^(2+)`.
If `lambda_(0)` is the threshold wavelength for photoelectric emission. `lambda` wavelength of light falling on the surface on the surface of metal, and `m` mass of electron. Then de Broglie wavelength of emitted electron is :-A. `[(h(lambdalambda_(0)))/(2mc(lambda_(0)-lambda))]overset(1)(2)`B. `[(h(lambda_(0)-lambda))/(2mclambdalambda_(0))]overset(1)(2)`C. `[(h(lambda-lambda_(0)))/(2mclambdalambda_(0))]overset(1)(2)`D. `[(hlambdalambda_(0))/(2mc)]overset(1)(2)`
If the threshold wavelength `(lambda_(0))` for ejection of electron from metal is `350 nm ` then work function for the photoelectric emission isA. `1.2 xx 10^-18 J`B. `1.2 xx 10^-20 J`C. `6 xx 10^-19 J`D. `6 xx 10^-12 J`
Elements up to atomic number `103` have been synthesized and studied. If a newly discovered element is found to have an atomic number `106`, its electronic configuration will beA. `[Rn]5 f^14 , 6d^4, 7s^2`B. `[Rn]5 f^14 , 6d^1, 7s^2 7p^3`C. `[Rn]5 f^14 , 6d^6, 7s^0`D. `[Rn]5 f^14 , 6d^5, 7s^1`
The kinetic energy of an electron in the second Bohr orbit of a hydrogen atom is [`a_0` is Bohr radius] :A. `(h^(2))/(4 pi^(2) ma_(0)^(2))`B. `(h^(2))/(16 pi^(2) ma_(0)^(2))`C. `(h^(2))/(32 pi^(2) ma_(0)^(2))`D. `(h^(2))/(64 pi^(2) ma_(0)^(2))`
The kinetic energy of an electron in the second Bohr orbit of a hydrogen atom is [`a_0` is Bohr radius] :A. `h^2/(4pi^2 ma_0^2)`B. `h^2/(16pi^2 ma_0^2)`C. `h^2/(32pi^2 ma_0^2)`D. `h^2/(64pi^2 ma_0^2)`

Discussion

No Comment Found

Related InterviewSolutions

Reply to Comment