1.

Compute the heat generated while transferring 96000 coulomb of charge in one hour through a potential difference of 50 V.

Answer»

Solution :`q = 96000 C `
t=1 h `=60xx60 = 3600 ` SEC
V= 50 V
Heat produced = work DONE
`H= QV= 96000 xx50 = 4.8xx10^(6)J`


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