Consider a gas enclosed in a box. Let the walls have an area of 0.01m^2. Let’s say a few molecules having their x-component of velocity =2m/s, hit a wall parallel to the yz plane. What will be the value of force on the wall in time dt? Let the number of molecules per unit volume be 10 & mass of each molecule be 10^-20kg.(a) 4*10^-19N(b) 4*10^-21N(c) 4/3*10^-21N(d) 4/3*10^-19NThe question was asked by my school principal while I was bunking the class.Enquiry is from Kinetic Theory of an Ideal Gas topic in portion Kinetic Theory of Physics – Class 11

Consider a gas enclosed in a box. Let the walls have an area of 0.01m^

1.	Consider a gas enclosed in a box. Let the walls have an area of 0.01m^2. Let’s say a few molecules having their x-component of velocity =2m/s, hit a wall parallel to the yz plane. What will be the value of force on the wall in time dt? Let the number of molecules per unit volume be 10 & mass of each molecule be 10^-20kg.(a) 410^-19N(b) 410^-21N(c) 4/310^-21N(d) 4/310^-19NThe question was asked by my school principal while I was bunking the class.Enquiry is from Kinetic Theory of an Ideal Gas topic in portion Kinetic Theory of Physics – Class 11
Answer» RIGHT option is (b) 410^-21N Best explanation: According to the assumptions of KTG, we will assume that the molecules COLLIDE elastically. The total momentum transferred to the wall is 2MV(1/2)nAvdt. 1/2 has been included because, on average, half the molecules NEAR that wall will be moving AWAY from the wall. Force will be momentum/time = nmAv^2 = 1010^-200.014 = 410^-21N.

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