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Consider a gas inside a box. It exerts some pressure on its walls. Find this value. GIven that number of molecules per unit volume be 20, mass of each molecule 10^-20kg, vx^2 = 1m^2/s^2.(a) 20*10^-20Pa(b) 20/3*10^-20Pa(c) 20/3*10^-19Pa(d) 20*10^-19PaI have been asked this question in examination.My question comes from Kinetic Theory of an Ideal Gas in portion Kinetic Theory of Physics – Class 11 |
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Answer» RIGHT option is (a) 20*10^-20Pa To explain I would SAY: Pressure is given by (1/3)nmv^2. v^2 = 3vx^2 = 3m^2/s^2. P = (1/3)*20*10^-20*3 = 20*10^-20Pa. |
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