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Consider a source moving towards an listener at a speed of 0.9v. Where v is the velocity of sound. Calculate the apparent frequency if the actual frequency is 600 Hz. |
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Answer» SOLUTION :Apparent frequency, `N.=((v)/(v-v_(s)))n` `v_(s)=0.9v,n=600Hz` `n.=((v)/(v-0.9v))600=((v )/(v(1-0.9)))600=(1)/(0.1)XX600` `n.=6000Hz` |
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