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Consider the beta decay `^198 Au rarr ^198 Hg ** + Beta^(-1) + vec v`. where `^198 Hg^**` represents a mercury nucleus in an excited state at energy `1.088 MeV` above the ground state. What can be the maximum kinetic energy of the electron emitted? The atomic mass of `^198 Au` is `197.968233 u` and that of `^198 Hg` is `197.966760 u`. |
Answer» Correct Answer - [0.2834 MeV] |
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