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Consider the circuit shown in the figure. Find voltage Vx.(a) 1(b) 1.25(c) 1.5(d) 1.75This question was posed to me during an online exam.I want to ask this question from Mesh Analysis in section Methods of Analyzing Circuits of Network Theory

Answer»

The CORRECT CHOICE is (b) 1.25

The best I can explain: Consider CURRENT I1 (CW) in the loop 1 and I2 (ACW) in the loop 2. So, the equations will be VX+I2-I1=0. I1=5/2=2.5A. I2=4Vx/4= Vx. Vx+Vx-2.5=0. Vx = 1.25V.



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