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Consider the following circuit. Determine the current flowing in the ammeter having 1Ω internal resistance in series with the 3Ω resistor.(a) 0.6(b) 0.7(c) 0.8(d) 0.9I got this question in an international level competition.The question is from Compensation Theorem topic in division Useful Theorems in Circuit Analysis of Network Theory

Answer»

The CORRECT CHOICE is (a) 0.6

The explanation: The current FLOWING in the ammeter having 1Ω internal RESISTANCE in series with the 3Ω resistor shown in the circuit is 0.6 A.

Current through 3Ω resistor = 0.67/(7 + (4||6||2)) = 0.08A. Ammeter READING = 0.67 – 0.08 = 0.59 ≅ 0.6A.



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