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Consider the following nuclear reaction, `._(92)^(238)M rarr ._(y)^(x)N + 2 ._(2)^(4)He ._(y)^(x) N rarr ._(B)^(A) L + 2beta^(+)`A. 140B. 144C. 142D. 146 |
Answer» Correct Answer - B `._(92)M^(238) rarr ._(y)N^(x) + 2 ._(2)He^(4)` `._(y)N^(x) rarr ._(B)L^(A) + 2 beta^(+)` `._(y)N^(230) overset((92 - 2 xx2)rarr N^((238 - 4 xx 2)) = ._(88)N^(230)` `._(88)N^(230) overset(2beta^(+))rarr ._((88 -2))L^((230)) = ._(86)L^(230)` Total no of neutrons in `._(86)L^(230)` `230 - 86 = 144` |
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