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Consider the line L 1 : x 1 y 2 z 1 312 +++ ==, L2 : x2y2z3 123A. 0 unitB. `17//sqrt(3)` unitsC. `41//sqrt(5)`D. `17//5sqrt(3)` units |
Answer» Correct Answer - D The shortest distance between `L_(1)` ad `L_(2)` is `|({(2-(-1))hati+(2-2)hatj+(3-(-1))hatk}.(-hati-7hatj+5hatk))/(5sqrt(3))|` `=|((3hati+4hatk).(-hati-7hatj+5hatk))/(5sqrt(3))|` `(17)/(5sqrt(3))` units |
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