1.

Consider the line L 1 : x 1 y 2 z 1 312 +++ ==, L2 : x2y2z3 123A. 0 unitB. `17//sqrt(3)` unitsC. `41//sqrt(5)`D. `17//5sqrt(3)` units

Answer» Correct Answer - D
The shortest distance between `L_(1)` ad `L_(2)` is
`|({(2-(-1))hati+(2-2)hatj+(3-(-1))hatk}.(-hati-7hatj+5hatk))/(5sqrt(3))|`
`=|((3hati+4hatk).(-hati-7hatj+5hatk))/(5sqrt(3))|`
`(17)/(5sqrt(3))` units


Discussion

No Comment Found

Related InterviewSolutions