

InterviewSolution
Saved Bookmarks
1. |
If the distance between the plane Ax 2y + z = d and the plane containing the lines2 1x=3 2y=4 3zand3 2x=4 3y=5 4zis 6 , then |d| is |
Answer» Correct Answer - `|d|=6` Equation of the plane containing the lines `(x-2)/(2)=(y-3)/(5)" and "(x-1)/(2)=(y-2)/(3)=(z-3)/(4)` is `a(x-2)+b(gamma-3)+c(z-4)=0" "...(i)` where, `3a+4b+5c=0" "…(ii)` `2a+3b+4c=0" "(iii)` and`a(1-2)+b(2-3)+c(2-3)=0` i.e.`" "a+b+c=0" "...(iv)` From Eqs. (ii) and (iii), `(a)/(1)=(b)/(-2)=(c)/(1),` which satisfy Eq. (iv). Plane through lines is `x-2y+z=0.` Given plane is `Ax-2y+z=d` is `sqrt(6).` `:.` Planes must be parallel, so A=1 and then `(|d|)/(sqrt(6))=sqrt(6)implies|d|=6` |
|