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Consider the parabola `y=x^(2)+7x+2` and the straight line `y=3x-3`. What is equation of the ellipse having foci `(+-2, 0)` the eccentricity `1/4` ?A. `x^(2)/64+y^(2)/60=1`B. `x^(2)/60+y^(2)/64=1`C. `x^(2)/20+y^(2)/24=1`D. `x^(2)/24+y^(2)/20=1` |
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Answer» Correct Answer - A `"Foci: "(+-2, 0), e= 1/4` `c=2, e=1/4=c/arArr2/arArra=8` `"We know, "a^(2)-b^(2)=c^(2)` `rArrb^(2)=a^(2)-c^(2)=8^(2)-2^(2)=64-4=60` `"Eqn of ellipse"rArrx^(2)/a^(2)+y^(2)/b^(2)=1` `rArr" "x^(2)/64+y^(2)/60=1` |
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