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The foci of the hyperbola `4x^(2)-9y^(2)-1=0` areA. `(+-sqrt(13),0)`B. `(+-sqrt(13)/6,0)`C. `(0,+-sqrt(13)/6)`D. None of these |
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Answer» Correct Answer - B `4x^(2)-9y^(2)=1` `x^(2)/(1/2)^(2)-y^(2)/(1/3)^(2)=1` `"eccentricity, e"=sqrt(1+(1/3)^(2)/(1/2)^(2))=sqrt(13)/3` `"foci "=(+-1/2xxsqrt(13)/3,0)=(+-sqrt(13)/6,0)` |
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