1.

Construct a Delta ABC in which angleB=45^(@), angleC=60^(@) and the perpendicular from the vertex A to base BC is 4.5 cm.

Answer»

Solution :Steps of CONSTRUCTION
(i) Draw any LINE `XY`.
(II) Take any point `D` on `XY` and draw `DE bot XY`.
(iii) Cut off `DA=4.5` cm along `DE`.
(iv) Through A draw `LM||XY`
(V) CONSTRUCT `angleLAB=45^(@)` and `anglwMAC=60^(@)`, meeting `XY` at `B` and `C` respectively. Then, `DeltaABC` is the required triangle.


Discussion

No Comment Found