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Construct a Delta ABC in which angleB=45^(@), angleC=60^(@) and the perpendicular from the vertex A to base BC is 4.5 cm. |
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Answer» Solution :Steps of CONSTRUCTION (i) Draw any LINE `XY`. (II) Take any point `D` on `XY` and draw `DE bot XY`. (iii) Cut off `DA=4.5` cm along `DE`. (iv) Through A draw `LM||XY` (V) CONSTRUCT `angleLAB=45^(@)` and `anglwMAC=60^(@)`, meeting `XY` at `B` and `C` respectively. Then, `DeltaABC` is the required triangle.
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