Construct a DeltaABC in which AB = 4 cm, BC = 5.2 cm and CA = 4.5 cm. – InterviewSolution

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1.	Construct a DeltaABC in which AB = 4 cm, BC = 5.2 cm and CA = 4.5 cm.
Answer» Solution :Steps of construction : 1. DRAW `BC = 5.2 cm.` 2. With `B` as centre and radius `4 cm`, draw an arc. 3. With `C` as centre and radius `4.5 cm`, draw another arc which cuts the first arc at`A`. 3. JOIN `AB` and `AC`. `therefore DeltaABC` is the required triangle.

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