1.

Construct a DeltaABC in which AB = 5 cm, AC = 4.5 cm and angleA = 60^(@).

Answer»

Solution :STEPS of construction :
1. DRAW `AB = 5 cm.`
2. Draw `anglePAB =60^(@)`
3. Cut`AC = 4.5 cm` from `AP.`
4. Join `BC`.
`therefore DeltaABC` is the required triangle.


Discussion

No Comment Found