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Construct a DeltaABC in which AB = 5 cm, AC = 4.5 cm and angleA = 60^(@). |
Answer» Solution :STEPS of construction : 1. DRAW `AB = 5 cm.` 2. Draw `anglePAB =60^(@)` 3. Cut`AC = 4.5 cm` from `AP.` 4. Join `BC`. `therefore DeltaABC` is the required triangle. ![]() |
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