Construct a DeltaABC in which AB = 5 cm, AC + BC = 8 cm and angleB = 6 – InterviewSolution

InterviewSolution

1.	Construct a DeltaABC in which AB = 5 cm, AC + BC = 8 cm and angleB = 60^(@).
Answer» SOLUTION :Steps of construction : 1. Draw `AB = 5 cm`. 2. Construct `angleABP = 60^(@)` and cut `BP = 8 cm. ` 3. Join `AP`. 4. Draw the perpendicular bisector of `AP` which intersect `BP` at `C`. 5. Join`AC`. `therefore DeltaABC` is the required triangle.

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