Construct a DeltaABC in which base BC = 5.2 cm, angleABC = 50^(@) and – InterviewSolution

InterviewSolution

1.	Construct a DeltaABC in which base BC = 5.2 cm, angleABC = 50^(@) and AB - AC = 2 cm.
Answer» SOLUTION :STEPS of construction : 1.Draw `BC = 5.3 CM.` 2. Construct `anglePBC = 50^(@)` and cut `BP = 2 cm.` 3. JOIN `PC.` 4. Draw the perpendicular bisector of `PC` which intersect `BP` produced at `A.` 5. Join `AC.` `THEREFORE DeltaABC` is the required triangle.

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