Construct a DeltaABC in which BC = 5 cm, angleB = 60^(@) and angleC = – InterviewSolution

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1.	Construct a DeltaABC in which BC = 5 cm, angleB = 60^(@) and angleC = 45^(@).
Answer» Solution :Steps of CONSTRUCTION : 1. Draw `BC = 5 cm.` 2. Draw `anglePBC = 60^(@)` and `angleQCB = 45^(@)`. 3. `BP` and `CQ` intersect at`A`. `therefore DeltaABC` is the required TRIANGLE.

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