Construct a DeltaABC in which BC = 5cm, angleB= 60^(@) and AC + AB = 7 – InterviewSolution

InterviewSolution

1.	Construct a DeltaABC in which BC = 5cm, angleB= 60^(@) and AC + AB = 7.5cm.
Answer» Solution :Given, in`DeltaABCBC = 5cm, angleB= 60^(@) and AC + AB = 7.5cm`.To CONSTRUCT the triangle `ABC` use the following steps. (i) Draw the base `BC = 5cm`. (ii) At the point `B` make an `angleXBC = 60^(@)` (iii) Cut a line segment BD equal to `AB +AC = 7.5 cm` from the ray BX. (iv) Join `DC`. (v) Make an `angleDCY = angleBDC`. (vi) Let `CY` INTERSECT `BX` at`A.` Then, `DeltaABC` is the required triangle.

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