Construct a DeltaABC in which BC = 8cm, angleB = 45^(@) and AB - AC = – InterviewSolution

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1.	Construct a DeltaABC in which BC = 8cm, angleB = 45^(@) and AB - AC = 3.5 cm.
Answer» Solution :Given that, in `DeltaABC`, `BC = 8 cm,` `angleB = 45^(@)` and `AB - AC = 3.5 cm` Steps of construction : 1. Draw the base `BC = 8 cm` 2. At the point `B` make an `angleXBC = 45^(@)`. 3. Cut the LINE segment `BD` equal to `AB - AC` = `3.5 cm` from the ray `BX.` 4. Join `DC.` 5. Draw the perpendicular bisector, say `PQ` of `DC.` Let it INTERSECT `BX` at a point`A.` 7. Join `AC.`

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