Construct a DeltaABC in which QR = 6 cm, angleQ = 60^(@)and PR - PQ = – InterviewSolution

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1.	Construct a DeltaABC in which QR = 6 cm, angleQ = 60^(@)and PR - PQ = 2 cm.
Answer» Solution :Given that, in `DeltaABC, QR = 6 cm, angleQ = 60^(@)` and `PR - PQ = 2 cm` Steps of Construction : 1. Draw the base `QR = 6 cm.` 2. At the point `Q` make an `angleXQR = 60^(@)`. 3. CUT line segment `QS = PR - PQ (= 2 cm)` from the line `QX` extended on opposite side of the segment `QR.` 4. Join `SR.` 5. Draw the perpendicular bisector `LM` of `SR.` 6. LET `LM` intersect `QX` at `P.` 7. Join `PR.`

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