1.

Construct a DeltaABC whose perimeter is 14 cm and sides are in the ratio 2 : 3 : 4.

Answer»

Solution :Steps of construction :
1. DRAW a line segment `PQ = 14 cm.`
2. Draw a ray `PX,` making an acute angle with `PQ`and drawn in the downward direction.
From `P,` set off `(2+3+4) = 9` equal DISTANCES along `PX.`
Mark points `L, M, N` on `PX` such that `PL = 2` units, `LM = 3` units and `MN = 4` units.
5. JOIN `NQ.`
Through `L` and `M,` draw `LB` `||` `NQ` and `MC` `||` `NQ`, cutting `PQ` at `B` and `C` respectively.
7. With `B` as centre and radius `BP,` draw an arc.
8. With `C` as centre and radius `CQ,` draw another arc, cutting the previous arc at `A.`
Join `AB` and `AC.`
Then, `DeltaABC` is the required triangle.


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