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Construct a right-angled Delta ABC in which angleA=90^(@), hypotenuse BC=6 cm and AB=4 cm. Justify your construction. |
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Answer» Solution :STEPS OF CONSTRUCTION (i) Draw a line segment `BC=6` cm. (II) Draw the right BISECTOR of `BC`, cutting `BC` at `O`. (iii) With `O` as centre and radius `OB`, draw a semicircle on `BC`. (iv) With `B` as centre and radius `4 cm`, draw an arc, cutting the semicircle at `A`. (v) JOIN `AB` and `AC.` Then, `Delta ABC` is the required triangle, right angled at `A`. JUSTIFICATION : We know that an angle in a semicircle is a right angle and therefore, `angleBAC=90^(@)`. Also, `BA=4` cm and `BC=6` cm. Hence, `Delta ABC` is the required triangle, right angled at `A`.
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