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Construct a right angled triangle whose base is 12 cm and sum of its hypotenuse and other side is 18 cm. |
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Answer» Solution :Given that, in `DeltaABC`, base `BC = 12 cm,` `angleB = 90^(@)` and `AB + BC = 18 cm.` 1.DRAW the base `BC = 12 cm.` 2. At the point `B,` make an `angleXBC = 90^(@)`. 3. Cut a line segment `BD = AB + AC= 18 cm` from the ray `BX.` 4. Join `DC.` Draw the perpendicular bisector `PQ` of `CD` to intersect `BD` at a point `A.` 6. Join `AC.` Then, `ABC` is the required right angled triangle.
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