Construct a square of side 3 cm.

1.	Construct a square of side 3 cm.
Answer» Solution :We know that, each angle of a square is right angle (i.e., `90^(@)`). To construct a square of side `3 cm`, use the following steps. (i) Draw a LINE segment `AB` of length `3cm` . (ii) Now, generate an angle of `90^(@)` at points `A` and `B` of the SEGLE of `90^(@)` at points `A` and `B` of the segment and plot the parallel LINES `AX` and `BY` at these points. (iii) Cut `AD` and `BC` of length `3 cm` from `AX` and `BY`, respectively. (iv) Draw an angle of `90^(@)` at any one of the point `C` or `D` and join both points by a line segment `CD` of length `3cm`. Thus , `ABCD` is the required square of side, `3cm`. Alternate Method To construct a square `ABCD` of side `3cm`, use the following steps (i) Draw a line segment `AB` of length `3cm` . (ii) Now, draw an angle `XAB = 90^(@)` at point `A` of line segment `AB.` (iii) Cut a line segment `AD = 3cm` from the ray `AX` and join `BD`. (iv)Now, from `D` point `C` is at a distance of `3cm` . So, having `D` as centre, draw an arc of radius `3cm`. (v) From `B`,point `C` is at a distance of `3cm`. So, having `B` as center, draw an arc of radius `3cm` which intersect PREVIOUS arc (obtained in step iv) at `C`. (vi) join `DC` and `BC`. Thus, `ABCD` is the required square of side `3cm.`

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