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Construct a triangle ABC, in which base BC =6 cm, AB+AC=9 cm and angleABC=45^(@) |
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Answer» Solution :Step 1: Draw `BC = 6 cm.` Step 2: Draw `bar(BX)`, such that `angleCBX=45^(@)`. Step 3: With `B` as the center and the radius as `AB+AC=9` cm, draw an arc to meet `bar(BX)` at `D`. JOIN `CD`. Step 4: Draw the perpendicular bisector of `bar(CD)` to interest `bar(BD)` at A. Join `CA`. `triangleABC` is the required triangle. Proof. As AQ is the perpendicular bisector of `CD`, `ACD` is an ISOSCELES triangle, hence `AD = AC` and `AB+AC=AB+AD=9cm.`
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