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Construct a triangle similar to a given triangle ABCsuch that each of its sides is (2)/(3)rd of the corresponding sides of the triangle ABC. It is given that AB=4cm, BC=5cm and AC=6cm . |
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Answer» Solution :Steps of Construction: 1. Take BC=5cm and construction `DeltaABC` with BA=4 cm and CA=6 cm. 2. Divide BC into THREE EQUAL PARTS. 3. Let C' be a point on BC such that `BC'=(2)/(3)BC`. 4. Draw A'C' parallel to AC through C' intersecting BA at A' . `DeltaAB'C'` is the required triangle.
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