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Construct a triangle whose sides are 3.6 cm, 3 cm and 4.8 cm. Bisect the smallest angle and measure each part. |
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Answer» Solution :STEPS OF CONSTRUCTION (i) DRAW `AB=3.6` cm. (ii) With `A` as centre and `3 cm` as RADIUS, draw an arc. (iii) With `B` as centre and `4.8` cm as radius, draw another arc, cutting the previous arc at `A`. (iv) Join `AC` and `BC`. Then, `Delta ABC` is the REQUIRED triangle. (v) Clearly, the angle opposite to the smallest side is smallest. So, `angleB` is the smallest angle. (VI) So, we draw `BD,` the bisector of `angleB`. On measuring, we find that `angleABD=angleCBD=20^(@)`.
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