1.

Construct a triangle whose sides are 3.6 cm, 3 cm and 4.8 cm. Bisect the smallest angle and measure each part.

Answer»

Solution :STEPS OF CONSTRUCTION
(i) DRAW `AB=3.6` cm.
(ii) With `A` as centre and `3 cm` as RADIUS, draw an arc.
(iii) With `B` as centre and `4.8` cm as radius, draw another arc, cutting the previous arc at `A`.
(iv) Join `AC` and `BC`.
Then, `Delta ABC` is the REQUIRED triangle.
(v) Clearly, the angle opposite to the smallest side is smallest.
So, `angleB` is the smallest angle.
(VI) So, we draw `BD,` the bisector of `angleB`.
On measuring, we find that `angleABD=angleCBD=20^(@)`.


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