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Construct an isosceles triangle whose vertical angle is 60^(@) and the altitude is 4.6 cm. |
Answer» SOLUTION :Steps of construction : 1. Draw a line `DE` and take a point `P` on it. 2. Draw `angleAPE = 90^(@)` and cut `PA = 4.6 cm.` 3. Draw `angleCAP = angleBAP = (1)/(2) xx 60^(@) = 30^(@)` which meet `DE` at `C` and `B` respectively. `therefore DELTAABC` is the required triangle. |
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