1.

Construct an isosceles triangle whose vertical angle is 60^(@) and the altitude is 4.6 cm.

Answer»

SOLUTION :Steps of construction :
1. Draw a line `DE` and take a point `P` on it.
2. Draw `angleAPE = 90^(@)` and cut `PA = 4.6 cm.`
3. Draw `angleCAP = angleBAP = (1)/(2) xx 60^(@) = 30^(@)` which meet `DE` at `C` and `B` respectively.
`therefore DELTAABC` is the required triangle.



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