Construct DeltaABC in which BC = 5.2 cm, angleB = 50^(@) and AC - AB = – InterviewSolution

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1.	Construct DeltaABC in which BC = 5.2 cm, angleB = 50^(@) and AC - AB = 2 cm.
Answer» Solution :Steps of construction : 1. Draw `BC = 5.2 cm.` 2. Construct `anglePBC = 50^(@)` 3. Produce `PB` and cut `BD = 2 cm.` 4. Join `CD` and draw the PERPENDICULAR BISECTOR of `CD` which intersect `BP` at `A`. Join `AC.` `therefore DELTAABC` is the required triangle.

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