Construct trianglePQR in which QR = 2.1 cm, angleP=46^(@) and PQ+PR=5. – InterviewSolution

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1.	Construct trianglePQR in which QR = 2.1 cm, angleP=46^(@) and PQ+PR=5.1 cm.
Answer» SOLUTION :STEP 1: construct `angleQS=PQ + PR=5.1` cm. Step 2: Construct `angleQSR =1/2(46^(@))=23^(@)`. Step 3: With Q as the center and the radius 2.1 cm (QR = 2.1cm), draw an ARC to intersect SX at R and `R^(')`. Step 4: Join (QR) or `(QR^('))` and draw the perpendicular BISECTOR of SR ( or `SR^('))` to intersect `bar(QS)` at P(or `P^('))`. PQR (or `P^(')QR^('))` is the required triangle.

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