Construct trianglePQR in which QR=3.2 cm, PQ+PR=5.9 cm and angleR-angl – InterviewSolution

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1.	Construct trianglePQR in which QR=3.2 cm, PQ+PR=5.9 cm and angleR-angleQ=60^(@)
Answer» SOLUTION :Step 1: Draw line segment `QR = 3.2 cm.` Step 2: Draw `bar(RX)`, such that `angleQRX = (90^(@)+(angleR-angleQ)/(2))=90^(@)+30^(@)=120^(@)`. Step 3: TAKING `Q` as the center and a radius equal to `5.9 cm` (PQ + PR), draw an arc intersecting `bar(RX)` at S. Step 4: Draw `RY`, such that `angleQRY=(angleR-angleQ)/(2) = 30^(@)`, intersecting `QS` at `T.` Step 6: Draw the PERPENDICULAR bisector of `bar(RT)` intersecting `bar(QS)` at `P.` Step 7: Join `P` and `R.` `PQR` is the required triangle.

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