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Construct trianglePQR in which QR=3.4 cm, angleP=50^(@) and PQ - PR = 1.2 cm. |
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Answer» Solution :Step 1: DRAW the ray, `QX`. Step 2: Mark the point S on `bar(QX)`, such that `QS=1.2 cm.` Step 3: Construct an angle equal to `180-1/2(180-50)=115^(@)` at S, such that `angleQSY=115^(@)`. Step 4: With `Q` as the center and radius = `3.4 cm`, draw an arc to meet `SY` at `R.` Step 5: Join `Q` and `R`. Step 6: Draw the perpendicular bisector of `SR` intersecting `QX` at `P`. Step 7: Join `PR`. `PQR` is the required TRIANGLE.
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