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ConstructtrianglePYQ such that, PY=6.3 cm,YQ=7.2 cm, PQ=5.8 cm. If (YZ)/(YQ)=(6)/(5), then construct triangle XYZ similar to triangle PYQ.

Answer»


Answer :If seg YQ is divided into 5 equal parts, then seg YZ will be 6 times each PART of seg YQ.
So, if we construct `triangle PYQ`, point Z will be on SIDE YQ, at a distance equal to 6 parts from Y.
Now, point X is the point of intersection of ray YP and a line through Z, PARALLEL to PQ.
`triangle XYZ` is the required triangle similar to `triangle PYQ`.


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