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ConstructtrianglePYQ such that, PY=6.3 cm,YQ=7.2 cm, PQ=5.8 cm. If (YZ)/(YQ)=(6)/(5), then construct triangle XYZ similar to triangle PYQ. |
Answer» So, if we construct `triangle PYQ`, point Z will be on SIDE YQ, at a distance equal to 6 parts from Y. Now, point X is the point of intersection of ray YP and a line through Z, PARALLEL to PQ. `triangle XYZ` is the required triangle similar to `triangle PYQ`. |
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