Convert -1+i into polar form.(a) \(\sqrt{2}\), 5π/4(b) \(\sqrt{2}\), 3π/4(c) –\(\sqrt{2}\), π/4(d) \(\sqrt{2}\), π/4The question was posed to me in an interview.Enquiry is from Argand Plane and Polar Representation in division Complex Numbers and Quadratic Equations of Mathematics – Class 11

Convert -1+i into polar form.(a) \(\sqrt{2}\), 5π/4(b) \(\sqrt{2}\),

1.	Convert -1+i into polar form.(a) \(\sqrt{2}\), 5π/4(b) \(\sqrt{2}\), 3π/4(c) –\(\sqrt{2}\), π/4(d) \(\sqrt{2}\), π/4The question was posed to me in an interview.Enquiry is from Argand Plane and Polar Representation in division Complex Numbers and Quadratic Equations of Mathematics – Class 11
Answer» Right choice is (b) \(\sqrt{2}\), 3π/4 To elaborate: r=\(\sqrt{x^2+y^2}=\sqrt{(-1)^2+1^2}=\sqrt{1+1}=\sqrt{2}\). r cos θ = -1 and r sin θ = 1 So, θ is in 2^nd quadrant SINCE sin is POSITIVE and cos is negative. tan θ = -1 => tan θ = -tan π/4 => tan θ = tan (π-π/4) = tan 3π/4 => θ=3π/4.

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