1.

If, α and β are the roots of the equation 2x^2 – 3x – 6 = 0, then what is the equation whose roots are α^2 + 2 and β^2 + 2?(a) 4x^2 + 49x + 118 =0(b) 4x^2 – 49x + 118 =0(c) 4x^2 – 49x – 118 =0(d) x^2 – 49x + 118 =0The question was posed to me in a national level competition.My doubt is from Quadratic Equations in division Complex Numbers and Quadratic Equations of Mathematics – Class 11

Answer»

The correct answer is (b) 4x^2 – 49x + 118 =0

The best I can explain: Let, y = x^2 + 2

Then, 2x^2 – 3X – 6 = 0

So, (3x)^2 = (2x^2 – 6)^2

[2(y-2) – 6]^2 = 9(y-2)

= 4x^2 – 49x + 118 = 0.



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