1.

If, (a + 1)x^2 + 2(a+1)x + (a – 2) = 0, then, for what parameter of ‘a’ the given equation have equal roots?(a) (-∞, -1)(b) [-1, ∞)(c) (0, 1)(d) Not possibleI got this question in an international level competition.This key question is from Applications of Quadratic Equations in portion Complex Numbers and Quadratic Equations of Mathematics – Class 11

Answer»

The correct option is (d) Not possible

Explanation: For, equal ROOTS, D = 0

Where, D = b^2 – 4ac

In the equation, (a + 1)x^2 + 2(a+1)x + (a – 2) = 0

D = [2(a+1)]^2 – 4 (a + 1)(a – 2)

= 4a^2 + 4 + 8a – 4{a^2 – 2a + a – 2}

= 4a^2 + 4 + 8a – 4a^2 + 4 a + 8 > 0

=> 12A + 12 = 0

=> 12a = -12

=> a = -1

So, from here it is clear that a = -1 is not possible because the equation is BECOMING linear.



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