Convert -1-i into polar form.(a) \(\sqrt{2}\), 5π/4(b) \(\sqrt{2}\), 3π/4(c) \(\sqrt{2}\), -3π/4(d) \(\sqrt{2}\), π/4This question was posed to me in an online interview.This interesting question is from Argand Plane and Polar Representation topic in division Complex Numbers and Quadratic Equations of Mathematics – Class 11

Convert -1-i into polar form.(a) \(\sqrt{2}\), 5π/4(b) \(\sqrt{2}\),

1.	Convert -1-i into polar form.(a) \(\sqrt{2}\), 5π/4(b) \(\sqrt{2}\), 3π/4(c) \(\sqrt{2}\), -3π/4(d) \(\sqrt{2}\), π/4This question was posed to me in an online interview.This interesting question is from Argand Plane and Polar Representation topic in division Complex Numbers and Quadratic Equations of Mathematics – Class 11
Answer» Right answer is (C) \(\SQRT{2}\), -3π/4 The BEST I can explain: R=\(\sqrt{x^2+y^2} = \sqrt{(-1)^2+1^2} = \sqrt{1+1} = \sqrt{2}\). r COS θ = -1 and r sin θ = -1 => θ is in 3^rd quadrant since sin and cos both negative. tan θ = 1 => θ= -3π/4.

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