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Convert the following . (i)25^@C to Kelvin (ii)200 K to .^@C |
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Answer» SOLUTION :(i)`T_K=T_(C)+273.15` `T_K`=25+273.15=298.15 K (II)`T._(@C)=T_K` -273.15 `T._(@C)=200-273.15 =-73.15^@C` |
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