1.

Convert the following . (i)25^@C to Kelvin (ii)200 K to .^@C

Answer»

SOLUTION :(i)`T_K=T_(C)+273.15`
`T_K`=25+273.15=298.15 K
(II)`T._(@C)=T_K` -273.15
`T._(@C)=200-273.15 =-73.15^@C`


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