InterviewSolution
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InterviewSolution
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`(d^2x)/(d y^2)` equalsA. `((d^(2)x)/(dy^(2)))^(-1)`B. `((d^(2)x)/(dy^(2)))((dy)/(dx))^(-3)`C. `((d^(2)x)/(dy^(2)))((dy)/(dx))^(-2)`D. `-((d^(2)x)/(dy^(2)))((dy)/(dx))^(-3)` |
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Answer» Correct Answer - D We have, `(dx)/(dy)=((dy)/(dx))^(-1)` `implies" "(d)/(dy)((dx)/(dy))=(d)/(dy){((dy)/(dx))^(-1)}` `implies" "(d^(2)x)/(dy^(2))=(d)/(dx){((dy)/(dx))^(-1)}(dx)/(dy)` `implies" "(d^(2)x)/(dy^(2))=-((dy)/(dx))^(-2)(d)/(dx)((dy)/(dx)).(dx)/(dy)` `implies" "(d^(2)x)/(dy^(2))=-((dy)/(dx))^(-3)((d^(2)y)/(dx^(2)))` |
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